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OffgridCalc

Off-Grid System Calculator: sizing solar, battery, charge controller and inverter

Cabin, tiny house, hunting lodge or shepherd's hut: an off-grid system has to work in the month with the least sun. That's exactly where this calculator starts – it picks the weakest month of your usage period from real PVGIS monthly data and derives panel power, battery capacity, charge controller current and inverter size from it.

The difference is dramatic: the same system needs several times the panel power for year-round use compared with summer only. Enter your devices and choose when you want to use the system.

Devices

Rated power from the label, actual runtime per day, and whether the device runs through the inverter (1) or directly on 12/24 V (0).

Solar

When and where should the system work?

The biggest lever: year-round the system has to cope with December, which makes it several times larger.

Reference sites: Boston, Kansas City and Phoenix (PVGIS data, 2005–2023 average).

For year-round systems a steep tilt pays off – it shifts yield into winter.

System

Voltage, battery and reserve

Up to about 1,000 W of inverter power 12 V, above that 24 V, from about 3,000 W 48 V.

LiFePO4 can be discharged to 85 %, lead-acid only to 50 % – that doubles the capacity needed.

Three days is a common baseline. Every day costs battery capacity directly.

Advanced settings

Buffer for shading, soiling and ageing. 20 % is typical.

Charge controller, cabling, soiling. 78–85 % with MPPT, considerably less with PWM.

Typically 85–92 % at rated load, worse at partial load.

Result

Required solar power

224 W

for 685 Wh per day in October

Consumption versus yield in the design month685 / 822 Wh
Battery capacity
208 Ah
at 12 V – equals 2,492 Wh
Charge controller
23 A
incl. 25 % reserve, MPPT recommended
Inverter
not needed
all devices run directly on 12/24 V
Daily consumption
685 Wh
57.1 Ah at 12 V
Design month
October · 4.59 kWh per kWp and day
Reserve without sun
3 days
this drives the battery size
  • Sized for October – outside your usage period the system will not be enough.
  • Fusing, cable sizes and lightning protection are not part of this calculation. DC circuits with high currents belong in qualified hands.
Show calculation
  1. 1Cooler: 45 W × 10 h direct = 450 Wh
  2. 2Laptop: 65 W × 3 h direct = 195 Wh
  3. 3LED lights: 10 W × 4 h direct = 40 Wh
  4. 4Daily consumption: 685 Wh = 57.1 Ah at 12 V
  5. 5Design month: October with 4.59 kWh per kWp and day
  6. 6Solar power: 685 Wh ÷ (4.59 × 80%) × (1 + 20%) = 224 W
  7. 7Battery: 685 Wh × 3 days ÷ 85% depth of discharge ÷ 12 V = 208 Ah
  8. 8Charge controller: 224 W ÷ 12 V × 1.25 = 23 A

 

How it's calculated

An off-grid system has four parts that have to match: panels, battery, charge controller and inverter. The chain is only as good as its weakest link – and everything hangs on one question: in which month does the system still have to work?

The design month decides everything

A panel in December delivers only a fraction of its June output. Anyone using a cabin in summer only therefore needs a fraction of the panels of a year-round installation. This calculator picks the weakest month of your usage period from the PVGIS monthly data and sizes everything for it.

US Midwest reference site, panels tilted south, 80 % system efficiency, 20 % reserve. In Central Europe the December figure is far lower still (about 0.6 kWh), which is why year-round off-grid systems there need very large arrays.
UsageDesign monthYield per kWp and dayPanels for 600 Wh/day
Summer only (May–Aug.)May or Augustapprox. 5.5 kWhapprox. 165 W
Spring to autumn (Mar.–Oct.)Octoberapprox. 3.3 kWhapprox. 275 W
Year-roundDecemberapprox. 1.8 kWhapprox. 500 W
solar power [W] = daily consumption ÷ (yield in the design month × system efficiency) × (1 + reserve) battery [Ah] = daily consumption × reserve days ÷ (depth of discharge × efficiency) ÷ system voltage charge controller [A] = solar power ÷ system voltage × 1.25 fuse [A] = inverter ÷ (system voltage × efficiency) × 1.25
665 Wh/day in October (3.3 kWh/kWp): 665 ÷ (3.3 × 0.8) × 1.2 ≈ 300 W; battery for 3 days of LiFePO4 ≈ 205 Ah at 12 V

Why system voltage matters

At the same power, current halves when you go from 12 V to 24 V. That means thinner cables, smaller fuses and cheaper charge controllers. Rule of thumb: up to about 1,000 W of inverter power use 12 V, above that 24 V, and from about 3,000 W use 48 V. A 2,000 W inverter at 12 V draws around 190 A – that calls for very heavy cable.

The factor 1.25 for the charge controller and fuse is standard design practice: panels can briefly exceed their rated output in cold, clear weather. Fusing the battery and wiring belongs in qualified hands.

Worked example

Cabin with LED lights, a mobile router and a small fridge on the inverter. Used from spring to autumn, panels tilted south, US Midwest, 12 V system with LiFePO4 and three reserve days.

Inputs

  • Devices:
  • LED-Licht: 10 W × 4 h/day × 0 1/0
  • Mobiler Router: 10 W × 8 h/day × 0 1/0
  • Kühlschrank 230 V: 60 W × 8 h/day × 1 1/0
  • Usage period: Spring to autumn (March–October)
  • Region: US Midwest
  • Panel orientation: South
  • Tilt: Tilted (30–35°)
  • System voltage: 12 V
  • Battery type: LiFePO4 (lithium)
  • Reserve days without sun: 3 days
  • Reserve on panel power: 20 %
  • Solar system efficiency: 80 %
  • Inverter efficiency: 88 %

Result

217 W

Required solar power

Battery capacity
202 Ah
Charge controller
23 A
Inverter
60 W
Daily consumption
665 Wh
Design month
October · 4.59 kWh per kWp and day
Reserve without sun
3 days

Calculation

  1. Kühlschrank 230 V: 60 W × 8 h via AC = 545 Wh
  2. Mobiler Router: 10 W × 8 h direct = 80 Wh
  3. LED-Licht: 10 W × 4 h direct = 40 Wh
  4. Daily consumption: 665 Wh = 55.5 Ah at 12 V
  5. Design month: October with 4.59 kWh per kWp and day
  6. Solar power: 665 Wh ÷ (4.59 × 80%) × (1 + 20%) = 217 W
  7. Battery: 665 Wh × 3 days ÷ 85% depth of discharge ÷ 12 V = 202 Ah
  8. Charge controller: 217 W ÷ 12 V × 1.25 = 23 A
  9. Inverter: 60 W for the largest AC device, battery fuse 7 A

The variables explained

Devices: power, runtime, output
Rated power from the label, actual runtime per day, and whether the device runs through the inverter (AC) or directly on 12/24 V.
Usage period
Sets the design month. The biggest lever in the whole calculation – year-round use costs several times the panel power of summer-only use.
Orientation and tilt
For year-round systems a steeper tilt pays off: it shifts yield into winter, where it's needed.
System voltage
12 V for small systems, 24 V from about 1,000 W, 48 V from about 3,000 W. Higher voltage means less current and thinner cables.
Battery type
LiFePO4 can be discharged to 85 %, lead-acid only to 50 % – for the same usable energy, lead needs nearly twice the capacity.
Reserve days
How many days without sun the battery should bridge. Three days is a common approach.

Common mistakes

  • Sizing for summer and using it in winter: December delivers a fraction of June – a summer system sits idle in winter.
  • Choosing too small a battery: three overcast days in a row are normal. Without reserve days the system runs empty regularly.
  • Counting a lead-acid battery at 100 %: only half is usable, otherwise its life drops sharply.
  • Sizing the charge controller tightly: panels briefly exceed their rating in the cold – 25 % reserve belongs in the calculation.
  • Running everything through the inverter: lights, pumps and USB devices straight on 12 V save the conversion losses.
  • Forgetting the battery fuse: a properly rated fuse between battery and inverter is not optional equipment.

Assumptions and limits

  • Yield data comes from PVGIS (2005–2023 average) for one reference site per region; shading from trees or buildings is not included.
  • Consumption is assumed constant across the year. In winter lights and heating controls usually add to it, in summer cooling does.
  • Inverter power is based on the largest single device; if several AC devices run at once, add them up.
  • Charge efficiency and depth of discharge come from typical manufacturer figures per battery technology.
  • Cable sizes, row spacing and the specific fusing are not part of this calculation – that needs proper planning.
  • Temperature effects are not modelled: below 0 °C usable capacity drops, and LiFePO4 must not be charged below freezing.

Frequently asked questions

How much solar do I need for a cabin?

It depends almost entirely on the usage period. For 600 Wh a day, summer-only use needs roughly 165 W in the US Midwest. Spring to autumn it's about 275 W, year-round about 500 W – and in Central Europe the year-round figure is closer to 1,500 W because December is so weak.

How big does an off-grid battery need to be?

Daily consumption × reserve days ÷ usable depth of discharge. At 600 Wh a day, three reserve days and LiFePO4 (85 % depth), that's about 2,100 Wh, i.e. roughly 175 Ah at 12 V. With lead-acid it would be nearly double.

12 V, 24 V or 48 V – which is right?

Up to about 1,000 W of inverter power 12 V is practical; above that the current gets unwieldy: 2,000 W at 12 V draws around 190 A. So use 24 V from 1,000 W and 48 V from about 3,000 W. At higher voltage, cables, fuses and controllers are considerably cheaper.

Which charge controller do I need?

Charge current = panel power ÷ system voltage, plus 25 % reserve. 500 W at 12 V gives about 52 A. MPPT almost always pays off: it harvests 10–30 % more than a PWM controller and allows higher panel voltages, so thinner cables from the panels to the controller.

Is a year-round off-grid system worth it?

Only with a large array or a second charging option. Because December is so weak, the system would have to be several times larger than for summer use – and that capacity sits idle the rest of the year. A common approach is to size for spring to autumn and add a generator or occasional grid charging.

How many reserve days should I plan for?

Three days is a good baseline – that's how long a typical spell of bad weather lasts. If you use the system in winter or depend on it, plan four to five. Every reserve day costs battery capacity directly.

Do I need an inverter?

Only for AC devices. Lights, pumps, fans, routers and USB chargers are all available in 12 V – that saves 12–18 % of conversion losses plus the inverter's idle draw. For a fridge, power tools or kitchen appliances there's no way around one.

What does a small off-grid system cost?

Component prices vary widely, which is why this calculator deliberately quotes none. As a guide: the battery is usually the largest share, followed by the panels. Reducing consumption saves on both at once.

Sources and background